why do i have 2 versions of gcc and g in Mac OS X?


i had fresh re-installation of mac os x yosemite before install xcode , commandlinetools.



seems have 2 versions of gcc , g++ in following 2 directories:

/usr/bin (both files 14kb) and
/library/developer/commandlinetools/usr/bin (g++ alias , gcc 19kb)

type "which gcc" in terminal gives me "/usr/bin/gcc", did "which g++" gives me "/usr/bin/g++", , means system use gcc , g++ in /usr/bin



so, questions are:

1. why have 2 versions of gcc , g++?

2. why gcc , g++ installed commandlinetools not specified default ones?

3. how ask mac os x point gcc , g++ in directory "/library/developer/commandlinetools/usr/bin"?


btw, installed commandlinetools according following:

http://railsapps.github.io/xcode-command-line-tools.html



however, got different output typing "gcc --version" (difference hightlighted):

configured with: --prefix=/application/xcode.app/contents/developer/usr --with-gxx-include-dir=/usr/include/c++/4.2.1 apple llvm version 6.0 (clang-600.0.54) (based on llvm 3.5svn) target: x86_64-apple-darwin14.0.0 thread model: posix



... rather /library/developer/commandlinetools/usr shown in web page above ...



i'm quite confused gcc/g++ being used mac osx ...
 

currently, gcc , g++ in /usr/bin what's known shims. capable of automatically determining path respective utilities, , forwarding receive them. path can either command line tools directory mentioned above, or xcode.
 


Forums Macs macOS OS X Yosemite (10.10)


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